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Solve.\newliney=4y = 4\newline–4x−3y=–16–4x − 3y = –16\newline(_____, _____)

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Q. Solve.\newliney=4y = 4\newline–4x−3y=–16–4x − 3y = –16\newline(_____, _____)
  1. Substitute y=4y = 4: First, we substitute y=4y = 4 into the equation −4x−3y=−16-4x − 3y = -16.\newlineThis gives us −4x−3(4)=−16-4x − 3(4) = -16.\newlineAfter simplifying, we get −4x−12=−16-4x - 12 = -16.
  2. Add 1212 to isolate −4x-4x: Next, we add 1212 to both sides of the equation to isolate −4x-4x. This gives us −4x=−16+12-4x = -16 + 12. After simplifying, we get −4x=−4-4x = -4.
  3. Divide by −4-4: Finally, we divide both sides of the equation by −4-4 to solve for xx. This gives us x=−4/−4x = -4 / -4. After simplifying, we get x=1x = 1.
  4. Find coordinate point: We found y=4y = 4 and x=1x = 1. Substitute these values in (x,y)(x, y) to get the coordinate point.\newlineThis gives us the coordinate point (1,4)(1, 4).

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