Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve using the quadratic formula.\newline5d2+8d+3=05d^2 + 8d + 3 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlined=d = _____ or d=d = _____

Full solution

Q. Solve using the quadratic formula.\newline5d2+8d+3=05d^2 + 8d + 3 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlined=d = _____ or d=d = _____
  1. Identify values: Identify the values of aa, bb, and cc in the quadratic equation 5d2+8d+3=05d^2 + 8d + 3 = 0. The quadratic equation is in the form ad2+bd+c=0ad^2 + bd + c = 0, so by comparison: a=5a = 5 b=8b = 8 c=3c = 3
  2. Substitute values: Substitute the values of aa, bb, and cc into the quadratic formula to find dd. The quadratic formula is d=b±b24ac2ad = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. So we have: d=(8)±(8)245325d = \frac{-(8) \pm \sqrt{(8)^2 - 4\cdot 5\cdot 3}}{2\cdot 5}
  3. Simplify discriminant: Simplify the expression under the square root (the discriminant). (8)2453=6460=4\sqrt{(8)^2 - 4\cdot 5\cdot 3} = \sqrt{64 - 60} = \sqrt{4}
  4. Continue simplifying: Continue simplifying the quadratic formula with the values found.\newlined=8±410d = \frac{-8 \pm \sqrt{4}}{10}\newlineSince 4=2\sqrt{4} = 2, we have:\newlined=8±210d = \frac{-8 \pm 2}{10}
  5. Find possible values: Find the two possible values for dd.\newlineFirst solution:\newlined=(8+2)/10=6/10=3/5d = (-8 + 2) / 10 = -6 / 10 = -3 / 5\newlineSecond solution:\newlined=(82)/10=10/10=1d = (-8 - 2) / 10 = -10 / 10 = -1
  6. Simplify solutions: Simplify the solutions and, if necessary, round to the nearest hundredth.\newlineThe first solution is already in simplest form as a fraction:\newlined=35d = -\frac{3}{5}\newlineThe second solution is an integer:\newlined=1d = -1\newlineNo rounding is necessary as both solutions are exact.

More problems from Solve a quadratic equation using the quadratic formula