Solve using substitution. y = –6 3x − 3y = –12 (_____, _____)

Identify Equations and Variable: Identify the given equations and the variable to substitute. We are given two equations: y = –6 3x − 3y = –12 We will substitute the value of y from the first equation into the second equation.Substitute Value of y: Substitute the value of y into the second equation. Substitute y = –6 into 3x − 3y = –12 to get: 3x − 3(-6) = –12Simplify After Substitution: Simplify the equation after substitution. 3x + 18 = –12Solve for x: Solve for x. Subtract 18 from both sides of the equation to isolate the term with x: 3x + 18 - 18 = –12 - 18 3x = –30Divide to Find x: Divide both sides by 3 to find the value of x. 3x / 3 = –30 / 3 x = –10

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Solve using substitution. $\newline$ $y = -6$ $\newline$ $3x - 3y = -12$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

y = -6

\newline

3x - 3y = -12

\newline

(_____, _____)

Identify Equations and Variable: Identify the given equations and the variable to substitute. $\newline$ We are given two equations: $\newline$ $y = -6$ $\newline$ $3x - 3y = -12$ $\newline$ We will substitute the value of $y$ from the first equation into the second equation.
Substitute Value of $y$ : Substitute the value of $y$ into the second equation. $\newline$ Substitute $y = -6$ into $3x - 3y = -12$ to get: $\newline$ $3x - 3(-6) = -12$
Simplify After Substitution: Simplify the equation after substitution. $3x + 18 = -12$
Solve for x: Solve for x. $\newline$ Subtract $18$ from both sides of the equation to isolate the term with $x$ : $\newline$ $3x + 18 - 18 = -12 - 18$ $\newline$ $3x = -30$
Divide to Find x: Divide both sides by $3$ to find the value of x. $\newline$ $\frac{3x}{3} = \frac{-30}{3}$ $\newline$ $x = -10$