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Solve using substitution.\newlinex=7x = 7\newline5x−4y=35x - 4y = 3\newline(_____, _____)

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Q. Solve using substitution.\newlinex=7x = 7\newline5x−4y=35x - 4y = 3\newline(_____, _____)
  1. Substitute xx into equation: Step 11: Substitute the value of xx into the second equation.\newlineGiven x=7x = 7, substitute it into 5x−4y=35x - 4y = 3.\newline5(7)−4y=35(7) - 4y = 3\newline35−4y=335 - 4y = 3
  2. Solve for y: Step 22: Solve for y.\newlineSubtract 3535 from both sides:\newline35−4y−35=3−3535 - 4y - 35 = 3 - 35\newline−4y=−32-4y = -32
  3. Isolate and find yy: Step 33: Divide both sides by −4-4 to isolate yy.−4y−4=−32−4\frac{-4y}{-4} = \frac{-32}{-4}y=8y = 8

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