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Solve using substitution.\newline−9x+8y=−15-9x + 8y = -15\newliney=6y = 6\newline(_____, _____)

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Q. Solve using substitution.\newline−9x+8y=−15-9x + 8y = -15\newliney=6y = 6\newline(_____, _____)
  1. Substitute y=6y = 6: Substitute y=6y = 6 into the equation –9x+8y=–15–9x + 8y = –15 and then simplify. This gives us –9x+8(6)=–15–9x + 8(6) = –15.
  2. Calculate 8×68 \times 6: Calculate 8×68 \times 6 to find the value that will replace 8y8y. This gives us 4848. So the equation becomes –9x+48=–15–9x + 48 = –15.
  3. Solve for x: Solve for x in the equation −9x+48=−15-9x + 48 = -15. To do this, first subtract 4848 from both sides of the equation to isolate the term with xx. This gives us −9x=−15−48-9x = -15 - 48.
  4. Divide by −9-9: Calculate –15–48–15 – 48 to find the value that will be equal to –9x–9x. This gives us –63–63. So the equation becomes –9x=–63–9x = –63.
  5. Calculate x=7x = 7: Divide both sides of the equation –9x=–63–9x = –63 by –9–9 to solve for xx. This gives us x=–63/–9x = –63 / –9.
  6. Write coordinate point: Calculate −63/−9-63 / -9 to find the value of x. This gives us x=7x = 7.
  7. Write coordinate point: Calculate −63/−9-63 / -9 to find the value of xx. This gives us x=7x = 7.We found that x=7x = 7 and y=6y = 6. Write the solution as a coordinate point. The coordinate point is (7,6)(7, 6).

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