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Solve using substitution.\newline8x+6y=148x + 6y = 14\newliney=9y = 9\newline(_____, _____)

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Q. Solve using substitution.\newline8x+6y=148x + 6y = 14\newliney=9y = 9\newline(_____, _____)
  1. Substitute y=9y = 9: Substitute y=9y = 9 into the first equation.\newlineWe are given 8x+6y=148x + 6y = 14 and y=9y = 9. Substitute 99 for yy in the first equation.\newline8x+6(9)=148x + 6(9) = 14\newline8x+54=148x + 54 = 14
  2. Solve for x: Solve for x.\newlineIsolate the variable term by subtracting 5454 from both sides of the equation.\newline8x+54−54=14−548x + 54 - 54 = 14 - 54\newline8x=−408x = -40
  3. Divide by 88: Divide both sides by 88 to find the value of xx.8x8=−408\frac{8x}{8} = \frac{-40}{8}x=−5x = -5
  4. Write as ordered pair: Write the solution as an ordered pair.\newlineWe found x=−5x = -5 and we are given y=9y = 9. The solution in the form of an ordered pair is (x,y)(x, y).\newlineThe solution is (−5,9)(-5, 9).

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