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Solve using substitution.\newline−2x+y=−14-2x + y = -14\newlinex=10x = 10\newline(_____, _____)

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Q. Solve using substitution.\newline−2x+y=−14-2x + y = -14\newlinex=10x = 10\newline(_____, _____)
  1. Substitute x=10x = 10: Substitute x=10x = 10 into the equation –2x+y=–14–2x + y = –14.\newlineCalculation: –2(10)+y=–14–2(10) + y = –14, which simplifies to –20+y=–14–20 + y = –14.
  2. Solve for y: Solve for y in the equation −20+y=−14-20 + y = -14.\newlineCalculation: Add 2020 to both sides to isolate yy, which gives us y=−14+20y = -14 + 20, and then y=6y = 6.
  3. Write coordinate point: We found that x=10x = 10 and y=6y = 6. Write the solution as a coordinate point.\newlineThe coordinate point is (10,6)(10, 6).

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