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Solve using elimination.\newline6x+3y=−126x + 3y = -12\newline−8x−3y=10-8x - 3y = 10\newline(_____, _____)

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Q. Solve using elimination.\newline6x+3y=−126x + 3y = -12\newline−8x−3y=10-8x - 3y = 10\newline(_____, _____)
  1. Write Equations: Write down the system of equations to be solved using elimination.\newline6x+3y=−126x + 3y = -12\newline−8x−3y=10-8x - 3y = 10
  2. Add Equations: Add the two equations together to eliminate the yy variable.\newline(6x+3y)+(–8x−3y)=–12+10(6x + 3y) + (–8x − 3y) = –12 + 10
  3. Find xx: Perform the addition to find the value of xx.6x−8x+3y−3y=−12+106x - 8x + 3y - 3y = -12 + 10−2x=−2-2x = -2
  4. Solve for x: Solve for x by dividing both sides of the equation by -2＂).\(\newline\$-2x / -2 = -2 / -2\)\(\newline\)\(x = 1\)
  5. Substitute \(x\): Substitute the value of \(x\) back into one of the original equations to solve for \(y\). We'll use the first equation.\[6(1) + 3y = -12\]\[6 + 3y = -12\]
  6. Isolate y: Subtract \(6\) from both sides of the equation to isolate the term with \(y\).\(\newline\)\(3y = -12 - 6\)\(\newline\)\(3y = -18\)
  7. Solve for y: Divide both sides of the equation by \(3\) to solve for y.\(\newline\)\(\frac{3y}{3} = \frac{-18}{3}\)\(\newline\)\(y = -6\)

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