Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve using elimination.\newline−3x−6y=12-3x - 6y = 12\newline3x+7y=−183x + 7y = -18\newline(_____, _____)

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 8right chevron icon
Solve a system of equations using eliminationright chevron icon

Full solution

Q. Solve using elimination.\newline−3x−6y=12-3x - 6y = 12\newline3x+7y=−183x + 7y = -18\newline(_____, _____)
  1. Write Equations: Write down the system of equations to be solved using elimination.\newline−3x−6y=12-3x - 6y = 12\newline3x+7y=−183x + 7y = -18
  2. Add Equations: Add the two equations together to eliminate the xx variable.\newline(−3x−6y)+(3x+7y)=12+(−18)(-3x - 6y) + (3x + 7y) = 12 + (-18)
  3. Perform Addition: Perform the addition to eliminate the xx variable. −3x+3x−6y+7y=12−18\,-3x + 3x - 6y + 7y = 12 - 18 0x+1y=−6\,0x + 1y = -6This simplifies to y=−6y = -6.
  4. Substitute and Solve (yy): Substitute y=−6y = -6 into one of the original equations to solve for xx. We'll use the first equation.\newline−3x−6(−6)=12-3x - 6(-6) = 12
  5. Perform Multiplication: Perform the multiplication and solve for xx. −3x+36=12\,-3x + 36 = 12
  6. Isolate x: Subtract 3636 from both sides of the equation to isolate the term with xx.\newline−3x+36−36=12−36-3x + 36 - 36 = 12 - 36\newline−3x=−24-3x = -24
  7. Divide and Solve xx: Divide both sides by –3–3 to solve for xx.–3x–3=–24–3\frac{–3x}{–3} = \frac{–24}{–3}x=8x = 8
  8. Write Solution: Write down the solution to the system of equations.\newlineThe solution is (x,y)=(8,−6)(x, y) = (8, -6).

More problems from Solve a system of equations using elimination

Question
Solve using substitution. 5x−2y=−7 5x - 2y = -7 x=−5 x = -5 (_,_)
Get tutor helpright-arrow

Posted 3 months ago

Question
Is (1,1)(1,1) a solution to this system of equations? \newline4x+10y=144x + 10y = 14\newlinex+6y=7x + 6y = 7\newlineChoices:\newline(A) yes \newline(B) no
Get tutor helpright-arrow

Posted 3 months ago

Question
Which describes the system of equations below?\newliney=–3x+9y = –3x + 9 \newliney=–3x+9y = –3x + 9 \newlineChoices:\newline(A) consistent and independent\text{(A) consistent and independent} \newline(B) consistent and dependent\text{(B) consistent and dependent} \newline(C) inconsistent\text{(C) inconsistent}
Get tutor helpright-arrow

Posted 3 months ago

Question
Solve using elimination. \newline7x−8y=−17 7x - 8y = -17 \newline −7x+3y=2 -7x + 3y = 2 \newline (____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 3 months ago

Question
Solve. \newlinex=−2 x = -2 \newline−2x+2y=−8 -2x + 2y = -8 \newline(____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 3 months ago

Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineAt a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases 33 hot dog meals and 33 hamburger meals, paying a total of $36\$36. Mr. Hogan buys 11 hot dog meal and 33 hamburger meals, spending $26\$26 in all. How much do the meals cost?\newlineHot dog meals cost $\$_______ each, and hamburger meals cost $\$________ each.
Get tutor helpright-arrow

Posted 3 months ago

Question
Solve the system of equations by substitution.\newline−3x−y−3z=−11-3x - y - 3z = -11\newlinez=5z = 5\newlinex−y+3z=19x - y + 3z = 19\newline(____.____,____)
Get tutor helpright-arrow

Posted 3 months ago

Question
Solve the system of equations by elimination.\newlinex−3y−2z=10 x - 3y - 2z = 10 \newline3x+2y+2z=14 3x + 2y + 2z = 14 \newline2x−3y−2z=16 2x - 3y - 2z = 16 \newline(_,_,_)(\_,\_,\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations.\newliney=x2+36x+3 y = x^2 + 36x + 3 \newliney=22x−37 y = 22x - 37 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_)(\_,\_)\newline(_,_)(\_,\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations.\newliney=−x−24 y = -x - 24 \newlinex2+y2=488 x^2 + y^2 = 488 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_) (\_,\_) \newline(_,_) (\_,\_)
Get tutor helpright-arrow

Posted 3 months ago

View all (162)