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Solve using elimination.\newline3x+6y=−123x + 6y = -12\newline−3x−4y=−2-3x - 4y = -2\newline(_____, _____)

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Q. Solve using elimination.\newline3x+6y=−123x + 6y = -12\newline−3x−4y=−2-3x - 4y = -2\newline(_____, _____)
  1. Write Equations: Write down the system of equations to be solved using elimination.\newline3x+6y=−123x + 6y = -12\newline−3x−4y=−2-3x - 4y = -2
  2. Add Equations: Add the two equations together to eliminate the xx variable.\newline(3x+6y)+(–3x−4y)=–12+(–2)(3x + 6y) + (–3x − 4y) = –12 + (–2)
  3. Find yy: Perform the addition to find the value of yy.3x−3x+6y−4y=−12−23x - 3x + 6y - 4y = -12 - 20x+2y=−140x + 2y = -142y=−142y = -14
  4. Solve for y: Divide both sides of the equation by 22 to solve for y.\newline2y÷2=−14÷22y \div 2 = -14 \div 2\newliney=−7y = -7
  5. Substitute for x: Substitute the value of yy back into one of the original equations to solve for xx. We can use the first equation.3x+6(−7)=−123x + 6(-7) = -12
  6. Solve for x: Perform the multiplication and solve for x.\newline3x−42=−123x - 42 = -12\newline3x=−12+423x = -12 + 42\newline3x=303x = 30
  7. Final Solution: Divide both sides of the equation by 33 to find the value of x.\newline3x÷3=30÷33x \div 3 = 30 \div 3\newlinex=10x = 10

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