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Use the following situation to solve problems 
5-7.
Five students received the same text message at 9:00 AM.
Each of them sent the message to 5 more students at 10:00 AM. Each of those students semt the message to 5 more students at 11:00 AM.
(3) Represent the situation with exponential expressions.
Simplify the expressions.
6 If the pattern continues, how many students will receive the text message at noon? Explain how to use the pattern to find the answer.
625 student will pon multiply the 
5×3×5 by anothe s
to get that or 
125 ×5=625 
qquad

qquad

qquad
9 Chin says that the value of 
2^(5) is 10 . Explain what Chin did wrong and find the correct value.
He multiplied 
2×5 but it should be 
2×2×2×2×2

qquad
164
Lesson 15 Numerical Expressions with Exponents
CCurriculum Associates, LLC Copying is I

Solve.\newlineUse the following situation to solve problems 57 5-7 .\newlineFive students received the same text message at 99:0000 AM.\newlineEach of them sent the message to 55 more students at 1010:0000 AM. Each of those students semt the message to 55 more students at 1111:0000 AM.\newline(33) Represent the situation with exponential expressions.\newlineSimplify the expressions.\newline66 If the pattern continues, how many students will receive the text message at noon? Explain how to use the pattern to find the answer.\newline625625 student will pon multiply the 5×3×5 5 \times 3 \times 5 by anothe s\newlineto get that or 125×5=625 125 \times 5=625 \qquad \newline \qquad \newline \qquad \newline99 Chin says that the value of 25 2^{5} is 1010 . Explain what Chin did wrong and find the correct value.\newlineHe multiplied 2×5 2 \times 5 but it should be 2×2×2×2×2 2 \times 2 \times 2 \times 2 \times 2 \newline \qquad \newline164164\newlineLesson 1515 Numerical Expressions with Exponents\newlineCCurriculum Associates, LLC Copying is I

Full solution

Q. Solve.\newlineUse the following situation to solve problems 57 5-7 .\newlineFive students received the same text message at 99:0000 AM.\newlineEach of them sent the message to 55 more students at 1010:0000 AM. Each of those students semt the message to 55 more students at 1111:0000 AM.\newline(33) Represent the situation with exponential expressions.\newlineSimplify the expressions.\newline66 If the pattern continues, how many students will receive the text message at noon? Explain how to use the pattern to find the answer.\newline625625 student will pon multiply the 5×3×5 5 \times 3 \times 5 by anothe s\newlineto get that or 125×5=625 125 \times 5=625 \qquad \newline \qquad \newline \qquad \newline99 Chin says that the value of 25 2^{5} is 1010 . Explain what Chin did wrong and find the correct value.\newlineHe multiplied 2×5 2 \times 5 but it should be 2×2×2×2×2 2 \times 2 \times 2 \times 2 \times 2 \newline \qquad \newline164164\newlineLesson 1515 Numerical Expressions with Exponents\newlineCCurriculum Associates, LLC Copying is I
  1. Students Messaging Progression: At 1111:0000 AM, each of the 2525 students sent the message to 55 more students. So, 2525 students ×5=125\times 5 = 125 students got the message at 1111:0000 AM.
  2. Noon Message Recipients: If the pattern continues, at noon, each of the 125125 students will send the message to 55 more students. So, 125125 students ×5=625\times 5 = 625 students will get the message at noon.
  3. Exponential Calculation: Calculating the correct value of 252^{5}: 2×2=42 \times 2 = 4, 4×2=84 \times 2 = 8, 8×2=168 \times 2 = 16, 16×2=3216 \times 2 = 32. So, 25=322^{5} = 32.

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