Solve.Use the following situation to solve problems 5−7.Five students received the same text message at 9:00 AM.Each of them sent the message to 5 more students at 10:00 AM. Each of those students semt the message to 5 more students at 11:00 AM.(3) Represent the situation with exponential expressions.Simplify the expressions.6 If the pattern continues, how many students will receive the text message at noon? Explain how to use the pattern to find the answer.625 student will pon multiply the 5×3×5 by anothe sto get that or 125×5=6259 Chin says that the value of 25 is 10 . Explain what Chin did wrong and find the correct value.He multiplied 2×5 but it should be 2×2×2×2×2164Lesson 15 Numerical Expressions with ExponentsCCurriculum Associates, LLC Copying is I
Q. Solve.Use the following situation to solve problems 5−7.Five students received the same text message at 9:00 AM.Each of them sent the message to 5 more students at 10:00 AM. Each of those students semt the message to 5 more students at 11:00 AM.(3) Represent the situation with exponential expressions.Simplify the expressions.6 If the pattern continues, how many students will receive the text message at noon? Explain how to use the pattern to find the answer.625 student will pon multiply the 5×3×5 by anothe sto get that or 125×5=6259 Chin says that the value of 25 is 10 . Explain what Chin did wrong and find the correct value.He multiplied 2×5 but it should be 2×2×2×2×2164Lesson 15 Numerical Expressions with ExponentsCCurriculum Associates, LLC Copying is I
Students Messaging Progression: At 11:00 AM, each of the 25 students sent the message to 5 more students. So, 25 students ×5=125 students got the message at 11:00 AM.
Noon Message Recipients: If the pattern continues, at noon, each of the 125 students will send the message to 5 more students. So, 125 students ×5=625 students will get the message at noon.
Exponential Calculation: Calculating the correct value of 25: 2×2=4, 4×2=8, 8×2=16, 16×2=32. So, 25=32.
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