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Let’s check out your problem:
Solve the equation.
\newline
∣
x
∣
=
4
|x|=4
∣
x
∣
=
4
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Math Problems
Algebra 1
Solve absolute value equations
Full solution
Q.
Solve the equation.
\newline
∣
x
∣
=
4
|x|=4
∣
x
∣
=
4
Understand absolute value equation:
The absolute value of
x
x
x
is the distance from zero on the number line, which doesn't consider direction.
Write possible solutions:
Write the possible solutions for
x
x
x
.
\newline
Since
∣
x
∣
=
4
|x| = 4
∣
x
∣
=
4
,
x
x
x
can be either
4
4
4
or
−
4
-4
−
4
.
\newline
x
=
4
x = 4
x
=
4
or
x
=
−
4
x = -4
x
=
−
4
More problems from Solve absolute value equations
Question
Solve for
u
u
u
.
\newline
∣
u
∣
−
4
≥
6
|u| - 4 \geq 6
∣
u
∣
−
4
≥
6
\newline
\newline
Write a compound inequality like
1
<
x
<
3
1 < x < 3
1
<
x
<
3
or like
x
<
1
x < 1
x
<
1
or
x
>
3
x > 3
x
>
3
. Use integers, proper fractions, or improper fractions in simplest form.
\newline
________
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Posted 2 months ago
Question
Convert
9
7
8
9 \frac{7}{8}
9
8
7
into an improper fraction.
\newline
Answer:
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Posted 2 months ago
Question
f
(
x
)
=
{
−
4
x
for
x
<
−
1
−
x
+
1
for
−
1
≤
x
≤
3
−
2
x
+
8
for
x
>
3
f(x)=\left\{\begin{array}{lll} -4 x & \text { for } & x<-1 \\ -x+1 & \text { for } & -1 \leq x \leq 3 \\ -2 x+8 & \text { for } & x>3 \end{array}\right.
f
(
x
)
=
⎩
⎨
⎧
−
4
x
−
x
+
1
−
2
x
+
8
for
for
for
x
<
−
1
−
1
≤
x
≤
3
x
>
3
\newline
Find
f
(
3
)
f(3)
f
(
3
)
\newline
Answer:
\newline
Get tutor help
Posted 2 months ago
Question
Question
\newline
Solve the system of equations.
\newline
y
=
22
x
−
38
y
=
x
2
+
11
x
−
14
\begin{array}{l} y=22 x-38 \\ y=x^{2}+11 x-14 \end{array}
y
=
22
x
−
38
y
=
x
2
+
11
x
−
14
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
−
,
−
)
(
−
,
−
)
\begin{array}{l} (-,-) \\ (-,-) \end{array}
(
−
,
−
)
(
−
,
−
)
\newline
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→
\rightarrow
→
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Posted 2 months ago
Question
A baseball player went up to bat
250
250
250
times in a season. He hit the ball
100
100
100
times. Find the rate of balls hit to times at bat. Express as a simplified fraction.
\newline
2
5
\frac{2}{5}
5
2
\newline
5
2
\frac{5}{2}
2
5
\newline
3
5
\frac{3}{5}
5
3
\newline
2
3
\frac{2}{3}
3
2
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Posted 2 months ago
Question
The digits
1
,
2
,
3
,
4
,
5
1,2,3,4,5
1
,
2
,
3
,
4
,
5
, and
6
6
6
are randomly arranged to form a three-digit number. (Digits are not repeated.) Find the probability that the number is even and greater than
600
600
600
.
\newline
The probability that the three-digit number is even and greater than
600
600
600
is
□
\square
□
.
\newline
(Type an integer or a simplified fraction.)
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Posted 2 months ago
Question
Use benchmark fractions to estimate sums and differences less than or gremet than
1
1
1
. Write each expresston in the correct answer space.
\newline
7
8
+
5
10
1
5
8
−
5
6
10
10
−
2
3
1
2
+
2
3
5
12
+
1
4
1
1
6
+
7
8
\begin{array}{l} \frac{7}{8}+\frac{5}{10} \\ 1 \frac{5}{8}-\frac{5}{6} \\ \frac{10}{10}-\frac{2}{3} \\ \frac{1}{2}+\frac{2}{3} \\ \frac{5}{12}+\frac{1}{4} \\ 1 \frac{1}{6}+\frac{7}{8} \\ \end{array}
8
7
+
10
5
1
8
5
−
6
5
10
10
−
3
2
2
1
+
3
2
12
5
+
4
1
1
6
1
+
8
7
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Posted 2 months ago
Question
Eric is sorting pencils into boxes. He put
16
16
16
pencils in the first box,
21
21
21
pencils in the second box,
26
26
26
pencils in the third box, and
31
31
31
pencils in the fourth box. What kind of sequence is this?
\newline
Choices:
\newline
(A) arithmetic
\newline
(B) geometric
\newline
(C) both
\newline
(D) neither
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Posted 1 month ago
Question
Given the definitions of
f
(
x
)
f(x)
f
(
x
)
and
g
(
x
)
g(x)
g
(
x
)
below, find the value of
g
(
f
(
2
)
)
g(f(2))
g
(
f
(
2
))
.
\newline
f
(
x
)
=
−
5
x
+
3
g
(
x
)
=
2
x
2
+
5
x
−
14
\begin{array}{l} f(x)=-5 x+3 \\ g(x)=2 x^{2}+5 x-14 \end{array}
f
(
x
)
=
−
5
x
+
3
g
(
x
)
=
2
x
2
+
5
x
−
14
\newline
Answer:
Get tutor help
Posted 2 months ago
Question
Solve for
t
t
t
.
\newline
∣
t
+
8
∣
≤
4
|t + 8| \leq 4
∣
t
+
8∣
≤
4
\newline
Write a compound inequality like
1
<
x
<
3
1 < x < 3
1
<
x
<
3
or like
x
<
1
x < 1
x
<
1
or
x
>
3
x > 3
x
>
3
. Use integers, proper fractions, or improper fractions in simplest form.
\newline
______
Get tutor help
Posted 1 month ago