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Solve the system of equations.\newliney=21x+44y = 21x + 44\newliney=x2+3x+25y = x^2 + 3x + 25\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=21x+44y = 21x + 44\newliney=x2+3x+25y = x^2 + 3x + 25\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Set Equations Equal: Set the two equations equal to each other since they both equal yy. This gives us 21x+44=x2+3x+2521x + 44 = x^2 + 3x + 25.
  2. Rearrange and Simplify: Rearrange the equation to set it to zero by subtracting 21x+4421x + 44 from both sides. This gives us x2+3x+2521x44=0x^2 + 3x + 25 - 21x - 44 = 0, which simplifies to x218x19=0x^2 - 18x - 19 = 0.
  3. Factor Quadratic Equation: Factor the quadratic equation x218x19=0x^2 - 18x - 19 = 0. This equation does not factor nicely, so we will use the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=18b = -18, and c=19c = -19.
  4. Calculate Discriminant: Calculate the discriminant Δ=b24ac\Delta = b^2 - 4ac which is Δ=(18)24(1)(19)\Delta = (-18)^2 - 4(1)(-19). This gives us Δ=324+76\Delta = 324 + 76, which simplifies to Δ=400\Delta = 400.
  5. Use Quadratic Formula: Since the discriminant is positive, we have two real solutions. Calculate the solutions using the quadratic formula: x=18±4002x = \frac{18 \pm \sqrt{400}}{2}. This simplifies to x=18±202x = \frac{18 \pm 20}{2}.
  6. Find Values of x: Find the two values of x. The first value is x=(18+20)/2x = (18 + 20) / 2 which simplifies to x=38/2x = 38 / 2, giving us x=19x = 19. The second value is x=(1820)/2x = (18 - 20) / 2 which simplifies to x=2/2x = -2 / 2, giving us x=1x = -1.
  7. Substitute x=19x = 19: Substitute x=19x = 19 into the original equation y=21x+44y = 21x + 44 to find the corresponding y-value. This gives us y=21(19)+44y = 21(19) + 44, which simplifies to y=399+44y = 399 + 44, giving us y=443y = 443.
  8. Substitute x=1x = -1: Substitute x=1x = -1 into the original equation y=21x+44y = 21x + 44 to find the corresponding y-value. This gives us y=21(1)+44y = 21(-1) + 44, which simplifies to y=21+44y = -21 + 44, giving us y=23y = 23.

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