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Solve the system of equations.\newliney=21x+41y = 21x + 41\newliney=x2+21x23y = x^2 + 21x - 23\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

Full solution

Q. Solve the system of equations.\newliney=21x+41y = 21x + 41\newliney=x2+21x23y = x^2 + 21x - 23\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Substitute yy into second equation: Substitute yy from the first equation into the second equation: y=x2+21x23y = x^2 + 21x - 23 becomes 21x+41=x2+21x2321x + 41 = x^2 + 21x - 23.
  2. Subtract 21x21x: Subtract 21x21x from both sides to get 41=x22341 = x^2 - 23.
  3. Add 2323: Add 2323 to both sides to find x2=64x^2 = 64.
  4. Take square root: Take the square root of both sides to find x=±8x = \pm 8.
  5. Substitute x=8x=8 into yy: Substitute x=8x = 8 into y=21x+41y = 21x + 41 to find yy. This gives us y=21(8)+41y = 21(8) + 41.
  6. Calculate yy for x=8x=8: Calculate yy for x=8x = 8: y=168+41y = 168 + 41, which is y=209y = 209.
  7. Substitute x=8x=-8 into yy: Now substitute x=8x = -8 into y=21x+41y = 21x + 41 to find yy. This gives us y=21(8)+41y = 21(-8) + 41.
  8. Calculate yy for x=8x=-8: Calculate yy for x=8x = -8: y=168+41y = -168 + 41, which is y=127y = -127.

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