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Solve the system of equations.\newliney=14x31y = -14x - 31\newliney=x227x+9y = x^2 - 27x + 9\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

Full solution

Q. Solve the system of equations.\newliney=14x31y = -14x - 31\newliney=x227x+9y = x^2 - 27x + 9\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Move and Simplify: Now, let's move everything to one side to get a quadratic equation.\newlinex227x+14x+9+31=0x^2 - 27x + 14x + 9 + 31 = 0\newlinex213x+40=0x^2 - 13x + 40 = 0
  2. Factor Quadratic Equation: Next, we need to factor the quadratic equation. \newline(x5)(x8)=0(x - 5)(x - 8) = 0
  3. Solve for x: Now, we solve for x by setting each factor equal to zero.\newlinex5=0x - 5 = 0 or x8=0x - 8 = 0\newlineSo, x=5x = 5 or x=8x = 8
  4. Find y-values: Let's find the corresponding y-values by plugging xx back into one of the original equations.\newlineFor x=5x = 5, y=14(5)31y = -14(5) - 31 which gives us y=7031y = -70 - 31 so y=101y = -101.
  5. Find y-values: Now, for x=8x = 8, y=14(8)31y = -14(8) - 31 which gives us y=11231y = -112 - 31 so y=143y = -143.
  6. Write Coordinates: Finally, we write the coordinates in exact form. The first coordinate is (5,101)(5, -101) and the second coordinate is (8,143)(8, -143).

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