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Solve the system of equations.\newliney=13x+39y = -13x + 39\newliney=x219x1y = x^2 - 19x - 1\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=13x+39y = -13x + 39\newliney=x219x1y = x^2 - 19x - 1\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Set Equations Equal: We have the following system of equations:\newliney=13x+39y = -13x + 39\newliney=x219x1y = x^2 - 19x - 1\newlineTo find the solution, we need to set the two equations equal to each other because they both equal yy.\newline13x+39=x219x1-13x + 39 = x^2 - 19x - 1
  2. Rearrange to Standard Form: Rearrange the equation to get a standard form of a quadratic equation by moving all terms to one side.\newlinex219x1+13x39=0x^2 - 19x - 1 + 13x - 39 = 0\newlinex26x40=0x^2 - 6x - 40 = 0
  3. Factor Quadratic Equation: Factor the quadratic equation to find the values of xx. We are looking for two numbers that multiply to 40-40 and add up to 6-6. These numbers are 10-10 and 44. (x10)(x+4)=0(x - 10)(x + 4) = 0
  4. Solve for x: Solve for x by setting each factor equal to zero.\newlinex10=0x - 10 = 0 or x+4=0x + 4 = 0\newlineThis gives us two solutions for x:\newlinex=10x = 10 or x=4x = -4
  5. Find Corresponding y-Values: Find the corresponding y-values for each x-value by substituting back into one of the original equations. We can use y=13x+39y = -13x + 39.\newlineFor x=10x = 10:\newliney=13(10)+39y = -13(10) + 39\newliney=130+39y = -130 + 39\newliney=91y = -91\newlineFor x=4x = -4:\newliney=13(4)+39y = -13(-4) + 39\newliney=52+39y = 52 + 39\newliney=91y = 91
  6. Write Coordinates: Write the coordinates in exact form.\newlineThe solutions to the system of equations are the points where the two graphs intersect, which are the xx-values we found and their corresponding yy-values.\newlineFirst Coordinate: (10,91)(10, -91)\newlineSecond Coordinate: (4,91)(-4, 91)

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