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Solve the system of equations by substitution. \newlinex+y+2z=−1x + y + 2z = -1 \newliney=−6y = -6 \newline−2x+y+2z=−4-2x + y + 2z = -4

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Solve a system of equations in three variables using substitutionright chevron icon

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Q. Solve the system of equations by substitution. \newlinex+y+2z=−1x + y + 2z = -1 \newliney=−6y = -6 \newline−2x+y+2z=−4-2x + y + 2z = -4
  1. Substitute y=−6y = -6: Substitute y=−6y = -6 into the first equation x+y+2z=−1x + y + 2z = -1.\newlinex+(−6)+2z=−1x + (-6) + 2z = -1\newlinex−6+2z=−1x - 6 + 2z = -1
  2. Add 66 to isolate x: Add 66 to both sides to isolate x+2zx + 2z.\newlinex+2z=−1+6x + 2z = -1 + 6\newlinex+2z=5x + 2z = 5
  3. Substitute y=−6y = -6: Substitute y=−6y = -6 into the third equation −2x+y+2z=−4-2x + y + 2z = -4.\newline−2x+(−6)+2z=−4-2x + (-6) + 2z = -4\newline−2x−6+2z=−4-2x - 6 + 2z = -4
  4. Add 66 to isolate −2x-2x: Add 66 to both sides to isolate −2x+2z-2x + 2z.\newline−2x+2z=−4+6-2x + 2z = -4 + 6\newline−2x+2z=2-2x + 2z = 2
  5. Divide by −2-2 to solve xx: Divide the entire equation by −2-2 to solve for xx.
    x=2−2x = \frac{2}{-2}
    x=−1x = -1

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