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Solve the system of equations by substitution.\newlinex−3y−z=16x - 3y - z = 16\newline−2x+3y−2z=−17-2x + 3y - 2z = -17\newlinez=3z = 3

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Q. Solve the system of equations by substitution.\newlinex−3y−z=16x - 3y - z = 16\newline−2x+3y−2z=−17-2x + 3y - 2z = -17\newlinez=3z = 3
  1. Substitute z=3z = 3: Substitute z=3z = 3 into the first equation x−3y−z=16x - 3y - z = 16.\newlinex−3y−3=16x - 3y - 3 = 16\newlinex−3y=19x - 3y = 19
  2. Substitute z=3z = 3: Substitute z=3z = 3 into the second equation −2x+3y−2z=−17-2x + 3y - 2z = -17.\newline−2x+3y−2×3=−17-2x + 3y - 2\times3 = -17\newline−2x+3y−6=−17-2x + 3y - 6 = -17\newline−2x+3y=−11-2x + 3y = -11
  3. Two Equations with Two Variables: Now we have two equations with two variables:\newline11) x−3y=19x - 3y = 19\newline22) −2x+3y=−11-2x + 3y = -11\newlineAdd the two equations to eliminate yy.\newline(x−3y)+(−2x+3y)=19+(−11)(x - 3y) + (-2x + 3y) = 19 + (-11)\newlinex−2x=8x - 2x = 8\newline−x=8-x = 8\newlinex=−8x = -8

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