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Solve the system of equations by elimination.\newlinex3y2z=20-x - 3y - 2z = -20\newline2xy+3z=16-2x - y + 3z = -16\newlinex2y2z=13x - 2y - 2z = -13

Full solution

Q. Solve the system of equations by elimination.\newlinex3y2z=20-x - 3y - 2z = -20\newline2xy+3z=16-2x - y + 3z = -16\newlinex2y2z=13x - 2y - 2z = -13
  1. Combine Equations to Eliminate x: First, let's add the first and third equations to eliminate x.\newline(x3y2z)+(x2y2z)=20+(13)(-x - 3y - 2z) + (x - 2y - 2z) = -20 + (-13)\newlinex+x3y2y2z2z=33-x + x - 3y - 2y - 2z - 2z = -33\newline5y4z=33-5y - 4z = -33
  2. Multiply and Combine Equations: Now, let's multiply the second equation by 22 so we can eliminate xx with the first equation.\newline2(2xy+3z)=2(16)2(-2x - y + 3z) = 2(-16)\newline4x2y+6z=32-4x - 2y + 6z = -32
  3. Solve System of Equations: Add the modified second equation to the first equation.\newline(x3y2z)+(4x2y+6z)=20+(32)(-x - 3y - 2z) + (-4x - 2y + 6z) = -20 + (-32)\newlinex4x3y2y2z+6z=52-x - 4x - 3y - 2y - 2z + 6z = -52\newline5x5y+4z=52-5x - 5y + 4z = -52
  4. Eliminate z: Now, let's solve the system of two equations we have:\newline5y4z=33-5y - 4z = -33\newline5x5y+4z=52-5x - 5y + 4z = -52\newlineWe can add these two equations to eliminate z.\newline(5y4z)+(5x5y+4z)=33+(52)(-5y - 4z) + (-5x - 5y + 4z) = -33 + (-52)\newline5y5x5y=85-5y - 5x - 5y = -85\newline5x10y=85-5x - 10y = -85
  5. Solve for y: Divide the last equation by 5-5 to simplify.5x10y=85-5x - 10y = -85x+2y=17x + 2y = 17
  6. Correct Previous Step: Now, let's solve for yy using the equation 5y4z=33-5y - 4z = -33. We can substitute xx from x+2y=17x + 2y = 17 into this equation. But wait, I made a mistake in the previous step, I should have divided by 5-5 correctly. Let's correct that. 5x10y=85-5x - 10y = -85 x+2y=17x + 2y = 17 should be x+2y=17x + 2y = -17

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