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Solve the system of equations by elimination.\newlinex2y3z=3x - 2y - 3z = -3\newlinex+2y+2z=2x + 2y + 2z = -2\newlinex+y+z=2-x + y + z = 2

Full solution

Q. Solve the system of equations by elimination.\newlinex2y3z=3x - 2y - 3z = -3\newlinex+2y+2z=2x + 2y + 2z = -2\newlinex+y+z=2-x + y + z = 2
  1. Eliminate yy by adding equations: Add the first and second equations to eliminate yy.(x2y3z)+(x+2y+2z)=3+(2)(x - 2y - 3z) + (x + 2y + 2z) = -3 + (-2)2xz=52x - z = -5
  2. Eliminate xx by adding equations: Add the first and third equations to eliminate xx.(x2y3z)+(x+y+z)=3+2(x - 2y - 3z) + (-x + y + z) = -3 + 2y2z=1-y - 2z = -1
  3. Eliminate yy by multiplying and adding equations: Multiply the second equation by 22 and add it to the third equation to eliminate yy.\newline2(x+2y+2z)+(x+y+z)=2(2)+22(x + 2y + 2z) + (-x + y + z) = 2(-2) + 2\newline2x+4y+4zx+y+z=4+22x + 4y + 4z - x + y + z = -4 + 2\newlinex+5y+5z=2x + 5y + 5z = -2

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