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Solve the system of equations by elimination.\newline3xy+z=2-3x - y + z = -2\newline2x2y+2z=20-2x - 2y + 2z = 20\newlinex+y+2z=1-x + y + 2z = -1

Full solution

Q. Solve the system of equations by elimination.\newline3xy+z=2-3x - y + z = -2\newline2x2y+2z=20-2x - 2y + 2z = 20\newlinex+y+2z=1-x + y + 2z = -1
  1. Combine equations to eliminate yy: First, let's add the second and third equations to eliminate yy.(2x2y+2z)+(x+y+2z)=20+(1)(-2x - 2y + 2z) + (-x + y + 2z) = 20 + (-1)2x2y+2zx+y+2z=19-2x - 2y + 2z - x + y + 2z = 193xy+4z=19-3x - y + 4z = 19
  2. Add equations to eliminate y: Now, let's add the first and the new equation to eliminate y.(3xy+z)+(3xy+4z)=2+19(-3x - y + z) + (-3x - y + 4z) = -2 + 193xy+z3xy+4z=17-3x - y + z - 3x - y + 4z = 176x2y+5z=17-6x - 2y + 5z = 17

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