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Solve the system of equations by elimination.\newline−2x+y+3z=2-2x + y + 3z = 2\newlinex+y+2z=−13x + y + 2z = -13\newline3x+3y−3z=153x + 3y - 3z = 15

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Solve a system of equations in three variables using eliminationright chevron icon

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Q. Solve the system of equations by elimination.\newline−2x+y+3z=2-2x + y + 3z = 2\newlinex+y+2z=−13x + y + 2z = -13\newline3x+3y−3z=153x + 3y - 3z = 15
  1. Multiply and set up: Step 11: Multiply the second equation by −2-2 to set up elimination with the first equation.
  2. Add for elimination: Step 22: Add the first and the new second equation to eliminate yy.
  3. Simplify third equation: Step 33: Multiply the third equation by 13\frac{1}{3} to simplify it.
  4. Add to eliminate yy: Step 44: Add the simplified third equation to the new second equation to eliminate yy.
  5. Solve for xx: Step 55: Solve for xx using the equation from Step 44.

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