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Solve the system of equations.\newline−9x+10y=3-9x + 10y = 3\newline3x−2y=−93x - 2y = -9\newline(____, ____)

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Solve a system of equations in three variables using eliminationright chevron icon

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Q. Solve the system of equations.\newline−9x+10y=3-9x + 10y = 3\newline3x−2y=−93x - 2y = -9\newline(____, ____)
  1. Write Equations: Step 11: Write down the system of equations.\newline−9x+10y=3-9x + 10y = 3\newline3x−2y=−93x - 2y = -9
  2. Eliminate y: Step 22: Use elimination method to eliminate y. Multiply the second equation by 55 to balance the coefficients of yy.\newline5(3x−2y)=5(−9)5(3x - 2y) = 5(-9)\newline15x−10y=−4515x - 10y = -45
  3. Add Equations: Step 33: Add the modified second equation to the first equation to eliminate yy.(−9x+10y)+(15x−10y)=3+(−45)(-9x + 10y) + (15x - 10y) = 3 + (-45)6x=−426x = -42
  4. Solve for x: Step 44: Solve for x.\newline6x=−426x = -42\newlinex=−426x = \frac{-42}{6}\newlinex=−7x = -7
  5. Substitute and Find y: Step 55: Substitute x=−7x = -7 back into one of the original equations to find yy. Use the second equation: 3x−2y=−93x - 2y = -9.3(−7)−2y=−93(-7) - 2y = -9−21−2y=−9-21 - 2y = -9−2y=12-2y = 12y=12−2y = \frac{12}{-2}y=−6y = -6

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