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Solve the system of equations.
{:[-2x+9y=11],[-5x+2y=-34]:}
x = ◻
y = ◻

Solve the system of equations.\newline2x+9y=115x+2y=34\begin{array}{l}-2 x+9 y=11 \\ -5 x+2 y=-34\end{array}\newlinex=x = \square \newliney=y = \square

Full solution

Q. Solve the system of equations.\newline2x+9y=115x+2y=34\begin{array}{l}-2 x+9 y=11 \\ -5 x+2 y=-34\end{array}\newlinex=x = \square \newliney=y = \square
  1. Write Equations: Write down the system of equations.\newlineThe system of equations is given by:\newline2x+9y=11-2x + 9y = 11\newline5x+2y=34-5x + 2y = -34\newlineWe will use the method of substitution or elimination to solve for xx and yy.
  2. Multiply Equations: Multiply the first equation by 55 and the second equation by 22 to make the coefficients of xx in both equations equal in magnitude.\newlineMultiplying the first equation by 55:\newline2x×5+9y×5=11×5-2x \times 5 + 9y \times 5 = 11 \times 5\newline10x+45y=55-10x + 45y = 55\newlineMultiplying the second equation by 22:\newline5x×2+2y×2=34×2-5x \times 2 + 2y \times 2 = -34 \times 2\newline10x+4y=68-10x + 4y = -68
  3. Add Equations: Add the two new equations together to eliminate xx. Adding the equations 10x+45y=55-10x + 45y = 55 and 10x+4y=68-10x + 4y = -68: (10x+45y)+(10x+4y)=55+(68)(-10x + 45y) + (-10x + 4y) = 55 + (-68) 20x+49y=13-20x + 49y = -13 This step is incorrect because we should have subtracted one equation from the other to eliminate xx, not added them together.

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