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Solve the system by substitution.

{:[-x+6y=30],[-y-2=x]:}

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Solve the system by substitution.\newlinex+6y=30y2=x \begin{aligned} -x+6 y & =30 \\ -y-2 & =x \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newlinex+6y=30y2=x \begin{aligned} -x+6 y & =30 \\ -y-2 & =x \end{aligned} \newline(,) (\square, \square)
  1. Solve for xx: Solve the second equation for xx. The second equation is y2=x-y - 2 = x. We can rewrite this as x=y2x = -y - 2.
  2. Substitute xx: Substitute xx in the first equation with the expression found in Step 11.\newlineThe first equation is x+6y=30-x + 6y = 30. Substituting xx gives us (y2)+6y=30-(-y - 2) + 6y = 30.
  3. Simplify the equation: Simplify the equation from Step 22.\newlineThis simplifies to y+2+6y=30y + 2 + 6y = 30, which further simplifies to 7y+2=307y + 2 = 30.
  4. Solve for y: Solve for y.\newlineSubtract 22 from both sides to get 7y=287y = 28. Then divide both sides by 77 to find y=4y = 4.
  5. Substitute yy: Substitute yy back into the equation x=y2x = -y - 2 to find xx. Substitute y=4y = 4 into x=y2x = -y - 2 to get x=42x = -4 - 2, which simplifies to x=6x = -6.
  6. Write the solution: Write the solution as an ordered pair x,yx, y. The solution is (6,4)\left(-6, 4\right).

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