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Solve the system by substitution. -4x+4y=-40 y=3x-4 (◻,◻)

Solve the system by substitution.\newline−4x+4y=−40-4x+4y=-40 \newline y=3x−4y=3x-4\newline(□,□)(\square,\square)

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Q. Solve the system by substitution.\newline−4x+4y=−40-4x+4y=-40 \newline y=3x−4y=3x-4\newline(□,□)(\square,\square)
  1. Substitute Equation 11: Substitute y=3x−4y = 3x - 4 into the first equation −4x+4y=−40-4x + 4y = -40.\newline−4x+4(3x−4)=−40-4x + 4(3x - 4) = -40
  2. Distribute and Simplify: Distribute 44 into the parentheses.\newline−4x+12x−16=−40-4x + 12x - 16 = -40
  3. Combine Like Terms: Combine like terms.\newline8x−16=−408x - 16 = -40
  4. Addition and Subtraction: Add 1616 to both sides of the equation.\newline8x−16+16=−40+168x - 16 + 16 = -40 + 16\newline8x=−248x = -24
  5. Solve for x: Divide both sides by 88 to solve for x.\newline8x8=−248\frac{8x}{8} = \frac{-24}{8}\newlinex=−3x = -3
  6. Substitute into Equation 22: Substitute x=−3x = -3 into y=3x−4y = 3x - 4 to solve for yy.\newliney=3(−3)−4y = 3(-3) - 4
  7. Calculate yy: Calculate the value of yy.y=−9−4y = -9 - 4y=−13y = -13

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