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Solve the system by substitution. {:[4x+3y=47],[-6x-3=y]:} (◻,◻)

Solve the system by substitution.\newline4x+3y=47−6x−3=y \begin{aligned} 4 x+3 y & =47 \\ -6 x-3 & =y \end{aligned} \newline(□,□) (\square, \square)

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Solve a system of equations in three variables using substitutionright chevron icon

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Q. Solve the system by substitution.\newline4x+3y=47−6x−3=y \begin{aligned} 4 x+3 y & =47 \\ -6 x-3 & =y \end{aligned} \newline(□,□) (\square, \square)
  1. Isolate y: Isolate yy in the second equation.\newlineThe second equation is given as −6x−3=y-6x - 3 = y. We can rewrite it as y=−6x−3y = -6x - 3.
  2. Substitute yy: Substitute the expression for yy into the first equation.\newlineThe first equation is 4x+3y=474x + 3y = 47. We substitute y=−6x−3y = -6x - 3 into this equation to get:\newline4x+3(−6x−3)=474x + 3(-6x - 3) = 47
  3. Solve for x: Solve for x.\newline4x−18x−9=474x - 18x - 9 = 47\newline−14x−9=47-14x - 9 = 47\newline−14x=47+9-14x = 47 + 9\newline−14x=56-14x = 56\newlinex=56−14x = \frac{56}{-14}\newlinex=−4x = -4
  4. Substitute xx into yy: Substitute the value of xx back into the expression for yy.y=−6(−4)−3y = -6(-4) - 3y=24−3y = 24 - 3y=21y = 21
  5. Write solution as ordered pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (−4,21)(-4, 21).

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