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Solve the right triangle with the given parts.

A=47.7^(@),B=42.3^(@)
ielect the correct answer below and, if necessary, fill in the answer boxes to complete your choice.
A. 
a= 
◻ 
b= 
◻

◻ (Round to one decimal place as needed.)
B. There is not enough information to solve the triangle.

Solve the right triangle with the given parts.\newlineA=47.7,B=42.3 \mathrm{A}=47.7^{\circ}, \mathrm{B}=42.3^{\circ} \newlineielect the correct answer below and, if necessary, fill in the answer boxes to complete your choice.\newlineA. a= a= \square b= \mathrm{b}= \square \newline \square (Round to one decimal place as needed.)\newlineB. There is not enough information to solve the triangle.

Full solution

Q. Solve the right triangle with the given parts.\newlineA=47.7,B=42.3 \mathrm{A}=47.7^{\circ}, \mathrm{B}=42.3^{\circ} \newlineielect the correct answer below and, if necessary, fill in the answer boxes to complete your choice.\newlineA. a= a= \square b= \mathrm{b}= \square \newline \square (Round to one decimal place as needed.)\newlineB. There is not enough information to solve the triangle.
  1. Find Angle C: Since we have a right triangle, we know that angle C is 9090 degrees. We can find angle C by subtracting the sum of angles A and B from 180180 degrees.\newlineC=180(A+B)C = 180 - (A + B)\newlineC=180(47.7+42.3)C = 180 - (47.7 + 42.3)\newlineC=18090C = 180 - 90\newlineC=90C = 90 degrees
  2. Use Sine Function: Now we have confirmed that angle CC is indeed 9090 degrees, which makes sense for a right triangle. We can use the sine and cosine functions to find the lengths of sides aa and bb. Let's use the sine function for angle AA to find side aa. \newlinesin(A)=oppositehypotenuse\sin(A) = \frac{\text{opposite}}{\text{hypotenuse}}\newlinesin(47.7)=ac\sin(47.7) = \frac{a}{c}
  3. Use Cosine Function: We don't have the length of the hypotenuse cc, so we can't directly calculate side aa yet. Let's use the cosine function for angle AA to find side bb.\newlinecos(A)=adjacenthypotenuse\cos(A) = \frac{\text{adjacent}}{\text{hypotenuse}}\newlinecos(47.7)=bc\cos(47.7) = \frac{b}{c}
  4. Find Side b: Again, we don't have the length of the hypotenuse cc, so we can't directly calculate side bb either. We need to use the sine function for angle BB to find side bb, since we know that side bb is the opposite side to angle BB.sin(B)=oppositehypotenuse\sin(B) = \frac{\text{opposite}}{\text{hypotenuse}}sin(42.3)=bc\sin(42.3) = \frac{b}{c}
  5. Apply Pythagorean Theorem: We can use the Pythagorean theorem to find the hypotenuse cc, since we have a right triangle.\newlinea2+b2=c2a^2 + b^2 = c^2\newlineBut we don't have the lengths of sides aa and bb, so we can't find cc yet. We need to find one of the sides first.
  6. Assume Hypotenuse: Let's assume the hypotenuse cc is 11 for simplicity, which allows us to find the lengths of aa and bb relative to cc.\newlinesin(47.7)=a1\sin(47.7) = \frac{a}{1}\newlinea=sin(47.7)a = \sin(47.7)
  7. Calculate Value of a: Now we calculate the value of aa using a calculator.asin(47.7 degrees)a \approx \sin(47.7 \text{ degrees})a0.736a \approx 0.736
  8. Calculate Value of b: Next, we calculate the value of b using the sine of angle BB. \newlinesin(42.3)=b1\sin(42.3) = \frac{b}{1}\newlineb=sin(42.3)b = \sin(42.3)
  9. Lengths of Sides: Now we calculate the value of bb using a calculator.bsin(42.3 degrees)b \approx \sin(42.3 \text{ degrees})b0.669b \approx 0.669
  10. Math Error: We have the lengths of sides aa and bb relative to the hypotenuse cc being 11. However, we assumed cc to be 11 without any basis, which is incorrect. We cannot assume the hypotenuse to be 11 without additional information. This is a math error.

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