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Let’s check out your problem:
Solve the inequality, 4-3(2-x)<10+x .
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Math Problems
Algebra 1
Solve advanced linear inequalities
Full solution
Q.
Solve the inequality,
4
−
3
(
2
−
x
)
<
10
+
x
4-3(2-x)<10+x
4
−
3
(
2
−
x
)
<
10
+
x
.
Distribute
−
3
-3
−
3
:
Distribute
−
3
-3
−
3
across the terms inside the parentheses:
4
−
3
(
2
−
x
)
=
4
−
6
+
3
x
4 - 3(2-x) = 4 - 6 + 3x
4
−
3
(
2
−
x
)
=
4
−
6
+
3
x
.
Combine like terms:
Combine like terms on the left side of the inequality:
4
−
6
+
3
x
=
−
2
+
3
x
4 - 6 + 3x = -2 + 3x
4
−
6
+
3
x
=
−
2
+
3
x
.
Rewrite inequality:
Rewrite the inequality with the simplified left side: -2 + 3x < 10 + x.
Subtract
x
x
x
:
Subtract
x
x
x
from both sides to get all
x
x
x
terms on one side: -2 + 3x - x < 10 + x - x.
Combine like terms:
Combine like terms: -2 + 2x < 10.
Add to isolate term:
Add
2
2
2
to both sides to isolate the term with
x
x
x
: -2 + 2 + 2x < 10 + 2.
Combine like terms:
Combine like terms: 2x < 12.
Divide to solve:
Divide both sides by
2
2
2
to solve for
x
x
x
: \frac{2x}{2} < \frac{12}{2}.
Simplify inequality:
Simplify the inequality: x < 6.
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