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Solve the following system of equations. (Hint: Use the quadratic formula.)


f(x)=2x^(2)-3x-10
oggle bookmark 
=-3x^(2)+20

(-2.2,5.9) and 
(3.2,0.9)

(0,-10) and 
(1,17)

(2.8,-3.0) and 
(-1.5,-1)

(-2.2,5.9) and 
(2.8,-3.0)

44. Solve the following system of equations. (Hint: Use the quadratic formula.)\newlinef(x)=2x23x10 f(x)=2 x^{2}-3 x-10 \newlineoggle bookmark =3x2+20 =-3 x^{2}+20 \newline(2.2,5.9) (-2.2,5.9) and (3.2,0.9) (3.2,0.9) \newline(0,10) (0,-10) and (1,17) (1,17) \newline(2.8,3.0) (2.8,-3.0) and (1.5,1) (-1.5,-1) \newline(2.2,5.9) (-2.2,5.9) and (2.8,3.0) (2.8,-3.0)

Full solution

Q. 44. Solve the following system of equations. (Hint: Use the quadratic formula.)\newlinef(x)=2x23x10 f(x)=2 x^{2}-3 x-10 \newlineoggle bookmark =3x2+20 =-3 x^{2}+20 \newline(2.2,5.9) (-2.2,5.9) and (3.2,0.9) (3.2,0.9) \newline(0,10) (0,-10) and (1,17) (1,17) \newline(2.8,3.0) (2.8,-3.0) and (1.5,1) (-1.5,-1) \newline(2.2,5.9) (-2.2,5.9) and (2.8,3.0) (2.8,-3.0)
  1. Set Equations Equal: Step 11: Set the equations equal to each other to find the xx-values where f(x)=g(x)f(x) = g(x).\newlineCalculation: 2x23x10=3x2+202x^2 - 3x - 10 = -3x^2 + 20
  2. Combine Like Terms: Step 22: Combine like terms to form a single quadratic equation.\newlineCalculation: 2x2+3x23x1020=02x^2 + 3x^2 - 3x - 10 - 20 = 0\newline5x23x30=05x^2 - 3x - 30 = 0
  3. Use Quadratic Formula: Step 33: Use the quadratic formula, x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, to find the roots.a=5a = 5, b=3b = -3, c=30c = -30 Calculation: x=3±(3)245(30)25x = \frac{3 \pm \sqrt{(-3)^2 - 4\cdot5\cdot(-30)}}{2\cdot5}
  4. Calculate Discriminant: Step 44: Calculate the discriminant b24acb^2 - 4ac.\newlineCalculation: (3)245(30)=9+600=609(-3)^2 - 4\cdot5\cdot(-30) = 9 + 600 = 609
  5. Solve for x: Step 55: Solve for x using the values from the quadratic formula.\newlineCalculation: x=3±60910x = \frac{3 \pm \sqrt{609}}{10}
  6. Simplify Roots: Step 66: Simplify the roots.\newlineCalculation: x=3+60910x = \frac{3 + \sqrt{609}}{10} and x=360910x = \frac{3 - \sqrt{609}}{10}
  7. Substitute for y: Step 77: Substitute the xx-values back into either f(x)f(x) or g(x)g(x) to find the corresponding yy-values.\newlineCalculation: For x=3+60910x = \frac{3 + \sqrt{609}}{10}, y=2(3+60910)23(3+60910)10y = 2\left(\frac{3 + \sqrt{609}}{10}\right)^2 - 3\left(\frac{3 + \sqrt{609}}{10}\right) - 10\newlineFor x=360910x = \frac{3 - \sqrt{609}}{10}, y=2(360910)23(360910)10y = 2\left(\frac{3 - \sqrt{609}}{10}\right)^2 - 3\left(\frac{3 - \sqrt{609}}{10}\right) - 10

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