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Let’s check out your problem:
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
5
x
+
1
2
(
6
x
−
10
)
=
−
(
−
8
x
+
4
)
−
1
5 x+\frac{1}{2}(6 x-10)=-(-8 x+4)-1
5
x
+
2
1
(
6
x
−
10
)
=
−
(
−
8
x
+
4
)
−
1
\newline
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Math Problems
Precalculus
Find the magnitude of a three-dimensional vector
Full solution
Q.
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
5
x
+
1
2
(
6
x
−
10
)
=
−
(
−
8
x
+
4
)
−
1
5 x+\frac{1}{2}(6 x-10)=-(-8 x+4)-1
5
x
+
2
1
(
6
x
−
10
)
=
−
(
−
8
x
+
4
)
−
1
\newline
Combine like terms:
Combine like terms on the right side of the equation.
\newline
−
(
−
8
x
+
4
)
−
1
=
8
x
−
4
−
1
-(-8x + 4) - 1 = 8x - 4 - 1
−
(
−
8
x
+
4
)
−
1
=
8
x
−
4
−
1
\newline
8
x
−
5
8x - 5
8
x
−
5
Multiply by
2
2
2
:
Multiply both sides of the equation by
2
2
2
to eliminate the fraction.
\newline
2
[
5
x
+
1
2
(
6
x
−
10
)
]
=
2
(
8
x
−
5
)
2[5x + \frac{1}{2}(6x - 10)] = 2(8x - 5)
2
[
5
x
+
2
1
(
6
x
−
10
)]
=
2
(
8
x
−
5
)
\newline
10
x
+
(
6
x
−
10
)
=
16
x
−
10
10x + (6x - 10) = 16x - 10
10
x
+
(
6
x
−
10
)
=
16
x
−
10
Combine like terms:
Combine like terms on the left side of the equation.
\newline
10
x
+
6
x
−
10
=
16
x
−
10
10x + 6x - 10 = 16x - 10
10
x
+
6
x
−
10
=
16
x
−
10
\newline
16
x
−
10
=
16
x
−
10
16x - 10 = 16x - 10
16
x
−
10
=
16
x
−
10
Subtract
16
x
16x
16
x
:
Subtract
16
x
16x
16
x
from both sides of the equation.
\newline
16
x
−
10
−
16
x
=
16
x
−
10
−
16
x
16x - 10 - 16x = 16x - 10 - 16x
16
x
−
10
−
16
x
=
16
x
−
10
−
16
x
\newline
−
10
=
−
10
-10 = -10
−
10
=
−
10
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Rewrite in simplest terms:
6
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(
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\newline
Answer:
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\newline
Answer:
\newline
Submit Answer
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2
2
2
. Given coordinates
A
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B
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A(-1,-1), B(9,1)
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P(4,4)
P
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\newline
The distance between
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P
P
and
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Q
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is
□
\square
□
.
\newline
(Simplify your answer. Type an exact answer using radicals as need
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x
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6
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6
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