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Solve the equation 
x^(3)+2x^(2)-5x-6=0 given that 2 is a zero of 
f(x)=x^(3)+2x^(2)-5x-6
The solution set is 
{:'. (Use a comma to separate answers as needed.)

Solve the equation x3+2x25x6=0 x^{3}+2 x^{2}-5 x-6=0 given that 22 is a zero of f(x)=x3+2x25x6 f(x)=x^{3}+2 x^{2}-5 x-6 \newlineThe solution set is { \{\because . (Use a comma to separate answers as needed.)

Full solution

Q. Solve the equation x3+2x25x6=0 x^{3}+2 x^{2}-5 x-6=0 given that 22 is a zero of f(x)=x3+2x25x6 f(x)=x^{3}+2 x^{2}-5 x-6 \newlineThe solution set is { \{\because . (Use a comma to separate answers as needed.)
  1. Divide by x - 22: Use synthetic division or polynomial long division to divide the polynomial by x2x - 2 since 22 is a zero of f(x)f(x).
  2. Perform synthetic division: Perform the synthetic division with 22 as the zero.\newline212562861430 \begin{array}{r|rrrr} 2 & 1 & 2 & -5 & -6 \\ & & 2 & 8 & 6 \\ \hline & 1 & 4 & 3 & 0 \\ \end{array} \newlineThe resulting polynomial after division is x2+4x+3x^2 + 4x + 3.
  3. Factor quadratic polynomial: Factor the quadratic polynomial x2+4x+3x^2 + 4x + 3.\newlinex2+4x+3=(x+1)(x+3) x^2 + 4x + 3 = (x + 1)(x + 3)
  4. Find other roots: Set each factor equal to zero to find the other roots.\newlinex+1=0andx+3=0 x + 1 = 0 \quad \text{and} \quad x + 3 = 0 \newlineSolving these equations gives us the roots x=1x = -1 and x=3x = -3.

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