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Solve the equation 
2x^(2)+16 x+56=x^(2) to the nearest tenth.
Answer: 
x=

Solve the equation 2x2+16x+56=x2 2 x^{2}+16 x+56=x^{2} to the nearest tenth.\newlineAnswer: x= x=

Full solution

Q. Solve the equation 2x2+16x+56=x2 2 x^{2}+16 x+56=x^{2} to the nearest tenth.\newlineAnswer: x= x=
  1. Set Equation to Zero: First, we need to set the equation to zero by moving all terms to one side.\newlineSubtract x2x^2 from both sides of the equation.\newline2x2+16x+56x2=x2x22x^2 + 16x + 56 - x^2 = x^2 - x^2\newlineThis simplifies to:\newlinex2+16x+56=0x^2 + 16x + 56 = 0
  2. Factor or Use Formula: Next, we need to factor the quadratic equation if possible, or use the quadratic formula to find the values of xx. The quadratic equation is x2+16x+56=0x^2 + 16x + 56 = 0. Let's try to factor it. We are looking for two numbers that multiply to 5656 and add up to 1616. The numbers 88 and 77 fit this requirement. So we can write the equation as: (x+8)(x+7)=0(x + 8)(x + 7) = 0
  3. Apply Zero Product Property: Now, we apply the zero product property, which states that if a product of two factors is zero, then at least one of the factors must be zero.\newlineSo we set each factor equal to zero and solve for xx:\newlinex+8=0x + 8 = 0 or x+7=0x + 7 = 0
  4. Solve for x: Solve the first equation for x:\newlinex+8=0x + 8 = 0\newlinex=8x = -8
  5. Solve for x: Solve the second equation for x:\newlinex+7=0x + 7 = 0\newlinex=7x = -7
  6. Final Solutions: We have found two solutions for xx. They are x=8x = -8 and x=7x = -7. Since we are asked to round to the nearest tenth, the solutions remain the same as they are already integers.

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