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Solve the D.E: 
(dy)/(dx)+yx=-x^(3)

Solve the D.E: dydx+yx=x3 \frac{d y}{d x}+y x=-x^{3}

Full solution

Q. Solve the D.E: dydx+yx=x3 \frac{d y}{d x}+y x=-x^{3}
  1. Identify type of equation: Identify the type of differential equation.\newlineThis is a first-order linear differential equation.
  2. Rewrite in standard form: Rewrite the equation in standard form. dydx+yx=x3\frac{dy}{dx} + yx = -x^3 can be written as dydx+xy=x3\frac{dy}{dx} + xy = -x^3.
  3. Find integrating factor: Find the integrating factor, μ(x)\mu(x).μ(x)=e(xdx)=ex22\mu(x) = e^{(\int x \, dx)} = e^{\frac{x^2}{2}}.
  4. Multiply by integrating factor: Multiply the entire differential equation by the integrating factor.\newlineex22dydx+ex22xy=x3ex22e^{\frac{x^2}{2}} \cdot \frac{dy}{dx} + e^{\frac{x^2}{2}} \cdot xy = -x^3 \cdot e^{\frac{x^2}{2}}.
  5. Recognize derivative of product: Recognize the left side of the equation as the derivative of a product. ddx[ye(x2/2)]=x3e(x2/2).\frac{d}{dx} [y \cdot e^{(x^2/2)}] = -x^3 \cdot e^{(x^2/2)}.
  6. Integrate both sides: Integrate both sides with respect to xx.ddx[ye(x2/2)]dx=x3e(x2/2)dx.\int \frac{d}{dx} [y \cdot e^{(x^2/2)}] dx = \int -x^3 \cdot e^{(x^2/2)} dx. ye(x2/2)=x3e(x2/2)dx+C.y \cdot e^{(x^2/2)} = -\int x^3 \cdot e^{(x^2/2)} dx + C.
  7. Solve integral: Solve the integral on the right side.\newlineThis step involves an error in integration; the integral of x3ex2/2-x^3 \cdot e^{x^2/2} is not elementary and cannot be expressed in terms of elementary functions.

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