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Let’s check out your problem:
Solve
x
−
5
2
\frac{x - 5}{2}
2
x
−
5
equals
x
+
2
6
\frac{x + 2}{6}
6
x
+
2
minus
3
3
3
.
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Home
Math Problems
Grade 7
Equivalent fractions
Full solution
Q.
Solve
x
−
5
2
\frac{x - 5}{2}
2
x
−
5
equals
x
+
2
6
\frac{x + 2}{6}
6
x
+
2
minus
3
3
3
.
Find Common Denominator:
Find a common denominator to combine the fractions on the right side of the equation.
\newline
(
6
)
(
x
−
5
2
)
=
(
2
)
(
x
+
2
6
)
−
(
6
)
(
3
)
(6)\left(\frac{x - 5}{2}\right) = (2)\left(\frac{x + 2}{6}\right) - (6)(3)
(
6
)
(
2
x
−
5
)
=
(
2
)
(
6
x
+
2
)
−
(
6
)
(
3
)
Simplify by Multiplying:
Simplify the equation by multiplying each term by the common denominator.
3
(
x
−
5
)
=
(
x
+
2
)
−
18
3(x - 5) = (x + 2) - 18
3
(
x
−
5
)
=
(
x
+
2
)
−
18
Distribute and Simplify:
Distribute the
3
3
3
on the left side and simplify the right side.
3
x
−
15
=
x
+
2
−
18
3x - 15 = x + 2 - 18
3
x
−
15
=
x
+
2
−
18
Combine Like Terms:
Combine like terms on the right side.
\newline
3
x
−
15
=
x
−
16
3x - 15 = x - 16
3
x
−
15
=
x
−
16
Subtract
x
x
x
Terms:
Subtract
x
x
x
from both sides to get the
x
x
x
terms on one side.
\newline
3
x
−
x
−
15
=
x
−
x
−
16
3x - x - 15 = x - x - 16
3
x
−
x
−
15
=
x
−
x
−
16
Isolate
x
x
x
Term:
Simplify both sides of the equation.
2
x
−
15
=
−
16
2x - 15 = -16
2
x
−
15
=
−
16
Add to Isolate
x
x
x
:
Add
15
15
15
to both sides to isolate the
x
x
x
term.
\newline
2
x
−
15
+
15
=
−
16
+
15
2x - 15 + 15 = -16 + 15
2
x
−
15
+
15
=
−
16
+
15
Divide to Solve for x:
Simplify both sides of the equation.
2
x
=
−
1
2x = -1
2
x
=
−
1
Divide to Solve for
x
x
x
:
Simplify both sides of the equation.
2
x
=
−
1
2x = -1
2
x
=
−
1
Divide both sides by
2
2
2
to solve for
x
x
x
.
x
=
−
1
2
x = -\frac{1}{2}
x
=
−
2
1
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\frac{2}{6}
6
2
in lowest terms.
\newline
‾
\underline{\hspace{1em}}
/
‾
\underline{\hspace{1em}}
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\newline
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\newline
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\newline
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\newline
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(
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b.
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8 \frac{1}{6}
8
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\newline
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