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Solve for zz.z25|z| - 2 \leq 5Write a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.

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Q. Solve for zz.z25|z| - 2 \leq 5Write a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.
  1. Isolate absolute value: We start with the given absolute value inequality:\newlinez25|z| - 2 \leq 5\newlineFirst, we isolate the absolute value expression by adding 22 to both sides of the inequality.\newlinez2+25+2|z| - 2 + 2 \leq 5 + 2\newlinez7|z| \leq 7
  2. Consider absolute value definition: Now we need to consider the definition of absolute value, which states that |z|\(\newline) is the distance of z\(\newline) from \(0\newline) on the number line. The inequality |z| \leq \(7\newline) means that z\(\newline) is within a distance of \(7\newline) from \(0\newline). This gives us two scenarios:\newline11. z \leq \(7\newline).\newline22. z \geq \(-7\newline).
  3. Write compound inequality: We can write these two scenarios as a compound inequality:\newline7z7-7 \leq z \leq 7\newlineThis compound inequality represents all the values of zz that satisfy the original inequality z25|z| - 2 \leq 5.

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