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Solve for zz.\newlinez+15−2=2z + \frac{15}{-2} = 2\newlinez=z = _____

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Full solution

Q. Solve for zz.\newlinez+15−2=2z + \frac{15}{-2} = 2\newlinez=z = _____
  1. Move term to isolate z: Isolate the variable zz on one side of the equation.\newlineTo do this, we need to move the term 15−2\frac{15}{-2} to the other side of the equation by adding its opposite to both sides.\newlinez+15−2+152=2+152z + \frac{15}{-2} + \frac{15}{2} = 2 + \frac{15}{2}
  2. Simplify both sides: Simplify both sides of the equation.\newlineSince 15−2\frac{15}{-2} and 152\frac{15}{2} are opposites, they cancel each other out on the left side. On the right side, we need to find a common denominator to add 22 and 152\frac{15}{2}.\newlinez=2+152z = 2 + \frac{15}{2}\newlinez=(2×2)/2+152z = \left(2 \times 2\right)/2 + \frac{15}{2}\newlinez=42+152z = \frac{4}{2} + \frac{15}{2}\newlinez=4+152z = \frac{4 + 15}{2}\newlinez=192z = \frac{19}{2}
  3. Convert to improper fraction: Convert the mixed number to an improper fraction if necessary.\newlineIn this case, 192\frac{19}{2} is already an improper fraction, so no conversion is needed.

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