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Solve for zz.\newline3(z12)=123(z - 12) = 12\newlinez=z = _____

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Q. Solve for zz.\newline3(z12)=123(z - 12) = 12\newlinez=z = _____
  1. Distribute 33: Distribute 33 to both terms inside the parentheses.\newlineCalculation: 3(z12)=3z363(z - 12) = 3z - 36
  2. Set up equation: Set up the equation with the distributed terms.\newlineCalculation: 3z36=123z - 36 = 12
  3. Add 3636: Add 3636 to both sides to isolate the term with zz.\newlineCalculation: 3z36+36=12+363z - 36 + 36 = 12 + 36
  4. Simplify equation: Simplify both sides of the equation.\newlineCalculation: 3z=483z = 48
  5. Divide by 33: Divide both sides by 33 to solve for zz.\newlineCalculation: z=483z = \frac{48}{3}