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Solve for zz.\newline2z−1=12z - 1 = 1\newlinez=___z = \_\_\_

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Full solution

Q. Solve for zz.\newline2z−1=12z - 1 = 1\newlinez=___z = \_\_\_
  1. Add 11 to isolate z: Add 11 to both sides of the equation to isolate the term with z.\newlineCalculation: 2z−1+1=1+12z - 1 + 1 = 1 + 1\newlineResult: 2z=22z = 2
  2. Divide by 22 for z: Divide both sides by 22 to solve for z.\newlineCalculation: 2z2=22\frac{2z}{2} = \frac{2}{2}\newlineResult: z=1z = 1

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