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Solve for zz.\newline11z+8-1 \leq -1z + 8

Full solution

Q. Solve for zz.\newline11z+8-1 \leq -1z + 8
  1. Isolate z: Isolate z by moving all other terms to the other side.\newline11z+8-1 \leq -1z + 8\newline181z-1 - 8 \leq -1z\newline91z-9 \leq -1z
  2. Divide and flip inequality: Divide both sides by 1-1, remembering to flip the inequality sign because we are dividing by a negative number.\newline9/1z-9 / -1 \geq z\newline9z9 \geq z

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