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Solve for $y$ . $\newline$ $4(y + 2) \geq 12$

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Solve advanced linear inequalities

Full solution

Q. Solve for

y

.

\newline

4(y + 2) \geq 12

Distribute $4$ : First, distribute the $4$ into the parentheses: $4(y + 2) \geq 12$ becomes $4y + 8 \geq 12$ .
Subtract $8$ : Next, subtract $8$ from both sides to isolate the term with $y$ : $4y + 8 - 8 \geq 12 - 8$ , which simplifies to $4y \geq 4$ .
Divide by $4$ : Then, divide both sides by $4$ to solve for y: $\frac{4y}{4} \geq \frac{4}{4}$ , so $y \geq 1$ .

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