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Solve for yy.\newline2+y=2(13y3)-2 + y = 2(\frac{1}{3}y - 3)\newliney=y = __

Full solution

Q. Solve for yy.\newline2+y=2(13y3)-2 + y = 2(\frac{1}{3}y - 3)\newliney=y = __
  1. Distribute and Simplify: Distribute 22 into the parentheses on the right side of the equation.\newline2+y=2×(13y)2×3-2 + y = 2 \times \left(\frac{1}{3}y\right) - 2 \times 3\newline2+y=23y6-2 + y = \frac{2}{3}y - 6
  2. Addition to Simplify: Add 22 to both sides to simplify.\newline2+2+y=23y6+2-2 + 2 + y = \frac{2}{3}y - 6 + 2\newliney=23y4y = \frac{2}{3}y - 4
  3. Subtract to Isolate y: Subtract 23y\frac{2}{3}y from both sides to isolate yy. \newliney23y=23y23y4y - \frac{2}{3}y = \frac{2}{3}y - \frac{2}{3}y - 4\newline13y=4\frac{1}{3}y = -4
  4. Multiply to Solve for y: Multiply both sides by 33 to solve for yy.3×(13y)=3×43 \times \left(\frac{1}{3}y\right) = 3 \times -4y=12y = -12