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Solve for x, (23 x-3)^(@)

1010. Solve for x x ,\newline(23x−3)∘ (23 x-3)^{\circ}

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Full solution

Q. 1010. Solve for x x ,\newline(23x−3)∘ (23 x-3)^{\circ}
  1. Take Square Root: First, let's take the square root of both sides to get rid of the exponent.\newline(23x−3)2=0\sqrt{(23x - 3)^2} = \sqrt{0}
  2. Simplify Square Root: Since the square root of 00 is 00, we have:\newline23x−3=023x - 3 = 0
  3. Add 33: Now, let's add 33 to both sides to isolate the term with x.\newline23x−3+3=0+323x - 3 + 3 = 0 + 3
  4. Isolate xx Term: This simplifies to: 23x=323x = 3
  5. Divide by 2323: Finally, divide both sides by 2323 to solve for xx.x=323x = \frac{3}{23}

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