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Let’s check out your problem:
Solve for
w
w
w
.
\newline
4
+
3
4
w
=
2
+
2
3
w
4 + \frac{3}{4}w = 2 + \frac{2}{3}w
4
+
4
3
w
=
2
+
3
2
w
\newline
w
w
w
= ____
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
Solve for
w
w
w
.
\newline
4
+
3
4
w
=
2
+
2
3
w
4 + \frac{3}{4}w = 2 + \frac{2}{3}w
4
+
4
3
w
=
2
+
3
2
w
\newline
w
w
w
= ____
Rearrange terms:
First, let's get all the
w
w
w
terms on one side and the constants on the other side.
4
+
3
4
w
−
2
3
w
=
2
−
4
4 + \frac{3}{4}w - \frac{2}{3}w = 2 - 4
4
+
4
3
w
−
3
2
w
=
2
−
4
Combining like terms:
3
4
w
−
2
3
w
=
−
2
\frac{3}{4}w - \frac{2}{3}w = -2
4
3
w
−
3
2
w
=
−
2
Find common denominator:
Next, find a common denominator for the
fractions
involving
w
w
w
, which is
12
12
12
.
\newline
(
9
12
)
w
−
(
8
12
)
w
=
−
2
(\frac{9}{12})w - (\frac{8}{12})w = -2
(
12
9
)
w
−
(
12
8
)
w
=
−
2
\newline
Simplify the
w
w
w
terms:
\newline
(
1
12
)
w
=
−
2
(\frac{1}{12})w = -2
(
12
1
)
w
=
−
2
Solve for w:
Finally, solve for w by multiplying both sides by
12
12
12
to clear the
fraction
.
\newline
w
=
−
2
×
12
w = -2 \times 12
w
=
−
2
×
12
\newline
w
=
−
24
w = -24
w
=
−
24
More problems from Solve linear equations: mixed review
Question
Solve for x.
\newline
(
3
4
)
x
=
12
(\frac{3}{4})x= 12
(
4
3
)
x
=
12
\newline
x
=
x =
x
=
______
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Posted 1 year ago
Question
Solve for x.
\newline
−
5
9
x
=
15
-\frac{5}{9}x= 15
−
9
5
x
=
15
\newline
x
=
x =
x
=
______
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Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
5
x
+
8
−
7
x
=
−
4
x
+
1
5x+8-7x=-4x+1
5
x
+
8
−
7
x
=
−
4
x
+
1
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
2
z
+
10
+
7
z
=
16
z
+
7
-2z+10+7z=16z+7
−
2
z
+
10
+
7
z
=
16
z
+
7
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
7
(
y
−
8
)
=
7
y
+
42
7(y-8)=7y+42
7
(
y
−
8
)
=
7
y
+
42
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
9
(
x
+
6
)
=
−
9
x
+
108
-9(x+6)=-9x+108
−
9
(
x
+
6
)
=
−
9
x
+
108
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
6
(
x
+
7
)
=
−
4
x
−
2
-6(x+7)=-4x-2
−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
4
x
−
7
+
10
x
=
−
7
+
6
x
-4x-7+10x=-7+6x
−
4
x
−
7
+
10
x
=
−
7
+
6
x
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
17
(
y
−
2
)
=
−
17
y
+
64
-17(y-2)=-17y+64
−
17
(
y
−
2
)
=
−
17
y
+
64
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
9z-6+7z=16z-6
9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
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