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Solve for vv.\newlinev35\lvert v - 3 \rvert \leq 5\newlineWrite a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______

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Q. Solve for vv.\newlinev35\lvert v - 3 \rvert \leq 5\newlineWrite a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______
  1. Rewrite the inequality: We have the inequality v35|v - 3| \leq 5. We need to solve for vv. The absolute value inequality xa|x| \leq a means that axa-a \leq x \leq a. So, we can rewrite the inequality without the absolute value as two separate inequalities: 5v35-5 \leq v - 3 \leq 5.
  2. Solve for left part: We will first solve the left part of the inequality: 5v3-5 \leq v - 3. We need to isolate vv by adding 33 to both sides of the inequality.\newline5+3v3+3-5 + 3 \leq v - 3 + 3\newline2v-2 \leq v
  3. Solve for right part: Now we will solve the right part of the inequality: v35v - 3 \leq 5. We need to isolate vv by adding 33 to both sides of the inequality.\newlinev3+35+3v - 3 + 3 \leq 5 + 3\newlinev8v \leq 8
  4. Combine results: Combining the results from Step 22 and Step 33, we get the compound inequality 2v8-2 \leq v \leq 8. This is the solution to the original absolute value inequality v35|v - 3| \leq 5.

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