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Solve for uu. \newline9u230u+25=09u^2 - 30u + 25 = 0\newlineWrite each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas. \newlineu=___u = \_\_\_

Full solution

Q. Solve for uu. \newline9u230u+25=09u^2 - 30u + 25 = 0\newlineWrite each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas. \newlineu=___u = \_\_\_
  1. Factor the quadratic: First, let's see if the quadratic can be factored easily. We're looking for two numbers that multiply to 9×259\times25 (which is 225225) and add up to 30-30.
  2. Identify correct numbers: The numbers that work are 15-15 and 15-15 because 15×15=225-15 \times -15 = 225 and 15+15=30-15 + -15 = -30.
  3. Write the quadratic: Now we can write the quadratic as (3u5)(3u5)=0(3u - 5)(3u - 5) = 0.
  4. Set factors equal to zero: Set each factor equal to zero: 3u5=03u - 5 = 0.
  5. Solve for u: Solve for u: 3u=53u = 5, so u=53u = \frac{5}{3}.
  6. Final solution: Since both factors were the same, there's only one solution: u=53u = \frac{5}{3}.

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