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Solve for $u$ . $\newline$ $3(u + 1) \geq 12$

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Solve advanced linear inequalities

Full solution

Q. Solve for

u

.

\newline

3(u + 1) \geq 12

Distribute $3$ : Distribute the $3$ across the parentheses. $\newline$ $3(u + 1) \geq 12$ $\newline$ $3u + 3 \geq 12$
Subtract to isolate: Subtract $3$ from both sides to isolate the term with the variable $u$ . $\newline$ $3u + 3 - 3 \geq 12 - 3$ $\newline$ $3u \geq 9$
Divide to solve: Divide both sides by $3$ to solve for $u$ . $\frac{3u}{3} \geq \frac{9}{3}$ $u \geq 3$

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