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Solve for tt.\newline−5≥t−3−6-5 \geq \frac{t}{-3} - 6

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Full solution

Q. Solve for tt.\newline−5≥t−3−6-5 \geq \frac{t}{-3} - 6
  1. Add 66 to isolate term: Add 66 to both sides to isolate the term with tt.−5+6≥t−3−6+6-5 + 6 \geq \frac{t}{-3} - 6 + 61≥t−31 \geq \frac{t}{-3}
  2. Multiply by −3-3 to solve: Multiply both sides by −3-3 to solve for tt. Remember to flip the inequality sign because we are multiplying by a negative number.\newline1×−3≤t−3×−31 \times -3 \leq \frac{t}{-3} \times -3\newline−3≤t-3 \leq t

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