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Solve for tt.\newline3(13t+23)=4t23\left(\frac{1}{3}t + \frac{2}{3}\right) = 4t - 2\newlinet=t = __

Full solution

Q. Solve for tt.\newline3(13t+23)=4t23\left(\frac{1}{3}t + \frac{2}{3}\right) = 4t - 2\newlinet=t = __
  1. Distribute Values: Distribute 33 to each term inside the parentheses.\newline3×(13t+23)=3×13t+3×233 \times (\frac{1}{3}t + \frac{2}{3}) = 3 \times \frac{1}{3}t + 3 \times \frac{2}{3}\newline=t+2= t + 2
  2. Set Up Equation: Set up the equation with the distributed values. t+2=4t2t + 2 = 4t - 2
  3. Isolate Variable: Isolate tt by subtracting tt from both sides.\newlinet+2t=4tt2t + 2 - t = 4t - t - 2\newline2=3t22 = 3t - 2
  4. Add to Isolate: Add 22 to both sides to further isolate 3t3t. \newline2+2=3t2+22 + 2 = 3t - 2 + 2\newline4=3t4 = 3t
  5. Divide to Solve: Divide both sides by 33 to solve for tt. \newline43=3t3\frac{4}{3} = \frac{3t}{3}\newlinet=43t = \frac{4}{3}