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Solve for tt.\newline2(t12)=62(t - 12) = 6\newlinet=t = _____\_\_\_\_\_

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Q. Solve for tt.\newline2(t12)=62(t - 12) = 6\newlinet=t = _____\_\_\_\_\_
  1. Distribute 22: Distribute the 22 across the parentheses.\newlineWe need to apply the distributive property to remove the parentheses. This means we multiply 22 by each term inside the parentheses.\newline2(t12)=2t2122(t − 12) = 2\cdot t − 2\cdot 12\newline2t24=62t − 24 = 6
  2. Add 2424: Add 2424 to both sides of the equation to isolate the term with the variable tt. We want to get tt by itself on one side of the equation, so we need to undo the subtraction of 2424. 2t24+24=6+242t - 24 + 24 = 6 + 24 2t=302t = 30
  3. Divide by 22: Divide both sides of the equation by 22 to solve for tt. Now we divide both sides by 22 to find the value of tt. 2t2=302\frac{2t}{2} = \frac{30}{2} t=15t = 15